(x^3+3x^2-4x-12)/(x^2+5x+6)

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Solution for (x^3+3x^2-4x-12)/(x^2+5x+6) equation: 


D( x )

x^2+5*x+6 = 0

x^2+5*x+6 = 0

x^2+5*x+6 = 0

x^2+5*x+6 = 0

DELTA = 5^2-(1*4*6)

DELTA = 1

DELTA > 0

x = (1^(1/2)-5)/(1*2) or x = (-1^(1/2)-5)/(1*2)

x = -2 or x = -3

x in (-oo:-3) U (-3:-2) U (-2:+oo)

(x^3+3*x^2-(4*x)-12)/(x^2+5*x+6) = 0

(x^3+3*x^2-4*x-12)/(x^2+5*x+6) = 0

x^3+3*x^2-4*x-12 = 0

x^3+3*x^2-4*x-12

x^2*(x+3)-4*x-12

x^2*(x+3)-4*(x+3)

(x^2-4)*(x+3)

x^2+5*x+6 = 0

x^2+5*x+6 = 0

DELTA = 5^2-(1*4*6)

DELTA = 1

DELTA > 0

x = (1^(1/2)-5)/(1*2) or x = (-1^(1/2)-5)/(1*2)

x = -2 or x = -3

(x+3)*(x+2) = 0

((x^2-4)*(x+3))/((x+3)*(x+2)) = 0

( x+3 )

x+3 = 0 // - 3

x = -3

( x^2-4 )

1*x^2 = 4 // : 1

x^2 = 4

x^2 = 4 // ^ 1/2

abs(x) = 2

x = 2 or x = -2

x in { -3} 

x in { -2} 

x = 2

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